Base | Representation |
---|---|
bin | 11001000000101101100101… |
… | …011111010000010101100101 |
3 | 112102110220111210201221201012 |
4 | 121000231211133100111211 |
5 | 103404220211142010203 |
6 | 1025541204123512005 |
7 | 32112150162450242 |
oct | 3100554537202545 |
9 | 472426453657635 |
10 | 110000110110053 |
11 | 3205a86a507539 |
12 | 10406912388605 |
13 | 494bc73044937 |
14 | 1d240688045c9 |
15 | cab54e212bd8 |
hex | 640b657d0565 |
110000110110053 has 2 divisors, whose sum is σ = 110000110110054. Its totient is φ = 110000110110052.
The previous prime is 110000110110043. The next prime is 110000110110109. The reversal of 110000110110053 is 350011011000011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105601786770529 + 4398323339524 = 10276273^2 + 2097218^2 .
It is a cyclic number.
It is not a de Polignac number, because 110000110110053 - 230 = 109999036368229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110000110110043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000055055026 + 55000055055027.
It is an arithmetic number, because the mean of its divisors is an integer number (55000055055027).
Almost surely, 2110000110110053 is an apocalyptic number.
It is an amenable number.
110000110110053 is a deficient number, since it is larger than the sum of its proper divisors (1).
110000110110053 is an equidigital number, since it uses as much as digits as its factorization.
110000110110053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 14.
Adding to 110000110110053 its reverse (350011011000011), we get a palindrome (460011121110064).
The spelling of 110000110110053 in words is "one hundred ten trillion, one hundred ten million, one hundred ten thousand, fifty-three".
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