110000110220131 has 2 divisors, whose sum is σ = 110000110220132. Its totient is φ = 110000110220130.

The previous prime is 110000110220069. The next prime is 110000110220171. The reversal of 110000110220131 is 131022011000011.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (131022011000011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110000110220131 - 2³³ = 109991520285539 is a prime.

It is a super-2 number, since 2×110000110220131² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110000110220171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000055110065 + 55000055110066.

It is an arithmetic number, because the mean of its divisors is an integer number (55000055110066).

Almost surely, 2^{110000110220131} is an apocalyptic number.

110000110220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

110000110220131 is an equidigital number, since it uses as much as digits as its factorization.

110000110220131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 110000110220131 its reverse (131022011000011), we get a palindrome (241022121220142).

The spelling of 110000110220131 in words is "one hundred ten trillion, one hundred ten million, two hundred twenty thousand, one hundred thirty-one".