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11000020000031 is a prime number
BaseRepresentation
bin1010000000010010010001…
…0010001101110100011111
31102221120222022021210012022
42200010210102031310133
52420211020110000111
635221201152130355
72213503515162416
oct240044422156437
942846868253168
1011000020000031
11356109a57a267
121297a645369bb
1361a3b36074aa
142a05920a047d
1514120830a2db
hexa012448dd1f

11000020000031 has 2 divisors, whose sum is σ = 11000020000032. Its totient is φ = 11000020000030.

The previous prime is 11000020000001. The next prime is 11000020000037. The reversal of 11000020000031 is 13000002000011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000020000031 - 226 = 10999952891167 is a prime.

It is a super-2 number, since 2×110000200000312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000019999973 and 11000020000018.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000020000037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500010000015 + 5500010000016.

It is an arithmetic number, because the mean of its divisors is an integer number (5500010000016).

Almost surely, 211000020000031 is an apocalyptic number.

11000020000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000020000031 is an equidigital number, since it uses as much as digits as its factorization.

11000020000031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 11000020000031 its reverse (13000002000011), we get a palindrome (24000022000042).

The spelling of 11000020000031 in words is "eleven trillion, twenty million, thirty-one", and thus it is an aban number and an uban number.