11000051341 has 2 divisors, whose sum is σ = 11000051342. Its totient is φ = 11000051340.

The previous prime is 11000051317. The next prime is 11000051347. The reversal of 11000051341 is 14315000011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9629496900 + 1370554441 = 98130^2 + 37021^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000051341 - 2⁷ = 11000051213 is a prime.

It is a super-2 number, since 2×11000051341² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000051347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500025670 + 5500025671.

It is an arithmetic number, because the mean of its divisors is an integer number (5500025671).

Almost surely, 2^11000051341 is an apocalyptic number.

It is an amenable number.

11000051341 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000051341 is an equidigital number, since it uses as much as digits as its factorization.

11000051341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 11000051341 its reverse (14315000011), we get a palindrome (25315051352).

The spelling of 11000051341 in words is "eleven billion, fifty-one thousand, three hundred forty-one".