Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101001001001000001011 |
3 | 10220011022120212212101201 |
4 | 100000131231021020023 |
5 | 121010310030012112 |
6 | 2201200531525031 |
7 | 142321162506466 |
oct | 20003555111013 |
9 | 3804276785351 |
10 | 1100010000907 |
11 | 394569a71904 |
12 | 159233159777 |
13 | 7c965b9a37c |
14 | 3b35294c2dd |
15 | 1d9317c9257 |
hex | 1001db4920b |
1100010000907 has 2 divisors, whose sum is σ = 1100010000908. Its totient is φ = 1100010000906.
The previous prime is 1100010000853. The next prime is 1100010000923. The reversal of 1100010000907 is 7090000100011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100010000907 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100010000937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005000453 + 550005000454.
It is an arithmetic number, because the mean of its divisors is an integer number (550005000454).
Almost surely, 21100010000907 is an apocalyptic number.
1100010000907 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010000907 is an equidigital number, since it uses as much as digits as its factorization.
1100010000907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63, while the sum is 19.
Adding to 1100010000907 its reverse (7090000100011), we get a palindrome (8190010100918).
The spelling of 1100010000907 in words is "one trillion, one hundred billion, ten million, nine hundred seven", and thus it is an aban number.
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