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110001000508 = 22723170809007
BaseRepresentation
bin110011001110010010…
…0100001000000111100
3101111221011021210210221
41212130210201000330
53300240224004013
6122311143111124
710642633035250
oct1463444410074
9344834253727
10110001000508
1142718773883
121939b1424a4
13a4b078a419
1454773a4260
152cdc24408d
hex199c92103c

110001000508 has 24 divisors (see below), whose sum is σ = 229567306752. Its totient is φ = 45093577584.

The previous prime is 110001000451. The next prime is 110001000539. The reversal of 110001000508 is 805000100011.

It is a super-2 number, since 2×1100010005082 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110001000491 and 110001000500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85403860 + ... + 85405147.

It is an arithmetic number, because the mean of its divisors is an integer number (9565304448).

Almost surely, 2110001000508 is an apocalyptic number.

It is an amenable number.

110001000508 is an abundant number, since it is smaller than the sum of its proper divisors (119566306244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110001000508 is a wasteful number, since it uses less digits than its factorization.

110001000508 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170809041 (or 170809039 counting only the distinct ones).

The product of its (nonzero) digits is 40, while the sum is 16.

Adding to 110001000508 its reverse (805000100011), we get a palindrome (915001100519).

The spelling of 110001000508 in words is "one hundred ten billion, one million, five hundred eight", and thus it is an aban number.

Divisors: 1 2 4 7 14 23 28 46 92 161 322 644 170809007 341618014 683236028 1195663049 2391326098 3928607161 4782652196 7857214322 15714428644 27500250127 55000500254 110001000508