11000100100993 has 2 divisors, whose sum is σ = 11000100100994. Its totient is φ = 11000100100992.

The previous prime is 11000100100903. The next prime is 11000100101021. The reversal of 11000100100993 is 39900100100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10280821402384 + 719278698609 = 3206372^2 + 848103^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000100100993 - 2²¹ = 11000098003841 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000100100903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050050496 + 5500050050497.

It is an arithmetic number, because the mean of its divisors is an integer number (5500050050497).

Almost surely, 2^{11000100100993} is an apocalyptic number.

It is an amenable number.

11000100100993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000100100993 is an equidigital number, since it uses as much as digits as its factorization.

11000100100993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 11000100100993 in words is "eleven trillion, one hundred million, one hundred thousand, nine hundred ninety-three".