Base | Representation |
---|---|
bin | 11001000000101110011010… |
… | …100101110001001110110011 |
3 | 112102110222210220010100211012 |
4 | 121000232122211301032303 |
5 | 103404224022224310344 |
6 | 1025541432350541135 |
7 | 32112211231125413 |
oct | 3100563245611663 |
9 | 472428726110735 |
10 | 110001001010099 |
11 | 32060187393971 |
12 | 10406b208077ab |
13 | 494c0857a3324 |
14 | 1d24110c72643 |
15 | cab5a254329e |
hex | 640b9a9713b3 |
110001001010099 has 2 divisors, whose sum is σ = 110001001010100. Its totient is φ = 110001001010098.
The previous prime is 110001001010083. The next prime is 110001001010119. The reversal of 110001001010099 is 990010100100011.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (990010100100011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110001001010099 - 24 = 110001001010083 is a prime.
It is not a weakly prime, because it can be changed into another prime (110001001015099) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000500505049 + 55000500505050.
It is an arithmetic number, because the mean of its divisors is an integer number (55000500505050).
Almost surely, 2110001001010099 is an apocalyptic number.
110001001010099 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001001010099 is an equidigital number, since it uses as much as digits as its factorization.
110001001010099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 23.
The spelling of 110001001010099 in words is "one hundred ten trillion, one billion, one million, ten thousand, ninety-nine".
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