Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101100001010100000011 |
3 | 10220011022121001220021202 |
4 | 100000131231201110003 |
5 | 121010310041144341 |
6 | 2201200534011415 |
7 | 142321163401346 |
oct | 20003555412403 |
9 | 3804277056252 |
10 | 1100010099971 |
11 | 39456a02a282 |
12 | 1592331a6b6b |
13 | 7c965c034a3 |
14 | 3b35297645d |
15 | 1d9317e879b |
hex | 1001db61503 |
1100010099971 has 2 divisors, whose sum is σ = 1100010099972. Its totient is φ = 1100010099970.
The previous prime is 1100010099967. The next prime is 1100010099977. The reversal of 1100010099971 is 1799900100011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100010099971 - 22 = 1100010099967 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1100010099977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005049985 + 550005049986.
It is an arithmetic number, because the mean of its divisors is an integer number (550005049986).
Almost surely, 21100010099971 is an apocalyptic number.
1100010099971 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010099971 is an equidigital number, since it uses as much as digits as its factorization.
1100010099971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5103, while the sum is 38.
Adding to 1100010099971 its reverse (1799900100011), we get a palindrome (2899910199982).
The spelling of 1100010099971 in words is "one trillion, one hundred billion, ten million, ninety-nine thousand, nine hundred seventy-one".
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