Base | Representation |
---|---|
bin | 11001000000101110011011… |
… | …001000011110101000000101 |
3 | 112102110222211112020122002001 |
4 | 121000232123020132220011 |
5 | 103404224032041441213 |
6 | 1025541433313545301 |
7 | 32112211401352546 |
oct | 3100563310365005 |
9 | 472428745218061 |
10 | 110001010108933 |
11 | 32060191538a69 |
12 | 10406b23875231 |
13 | 494c08763a958 |
14 | 1d241121604cd |
15 | cab5a323e1dd |
hex | 640b9b21ea05 |
110001010108933 has 2 divisors, whose sum is σ = 110001010108934. Its totient is φ = 110001010108932.
The previous prime is 110001010108877. The next prime is 110001010108967. The reversal of 110001010108933 is 339801010100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93394790153604 + 16606219955329 = 9664098^2 + 4075073^2 .
It is a cyclic number.
It is not a de Polignac number, because 110001010108933 - 233 = 109992420174341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110001010138933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000505054466 + 55000505054467.
It is an arithmetic number, because the mean of its divisors is an integer number (55000505054467).
Almost surely, 2110001010108933 is an apocalyptic number.
It is an amenable number.
110001010108933 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001010108933 is an equidigital number, since it uses as much as digits as its factorization.
110001010108933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 28.
Adding to 110001010108933 its reverse (339801010100011), we get a palindrome (449802020208944).
The spelling of 110001010108933 in words is "one hundred ten trillion, one billion, ten million, one hundred eight thousand, nine hundred thirty-three".
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