Search a number
-
+
110001022102022 = 255000511051011
BaseRepresentation
bin11001000000101110011011…
…110110001110101000000110
3112102110222212100210221111112
4121000232123312032220012
5103404224043124231042
61025541434423005022
732112211605323042
oct3100563366165006
9472428770727445
10110001022102022
113206019828a607
1210406b27899772
13494c089c7975c
141d241139a3022
15cab5a430c982
hex640b9bd8ea06

110001022102022 has 4 divisors (see below), whose sum is σ = 165001533153036. Its totient is φ = 55000511051010.

The previous prime is 110001022102019. The next prime is 110001022102063. The reversal of 110001022102022 is 220201220100011.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 110001022101988 and 110001022102006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500255525504 + ... + 27500255525507.

It is an arithmetic number, because the mean of its divisors is an integer number (41250383288259).

Almost surely, 2110001022102022 is an apocalyptic number.

110001022102022 is a deficient number, since it is larger than the sum of its proper divisors (55000511051014).

110001022102022 is an equidigital number, since it uses as much as digits as its factorization.

110001022102022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55000511051013.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 110001022102022 its reverse (220201220100011), we get a palindrome (330202242202033).

The spelling of 110001022102022 in words is "one hundred ten trillion, one billion, twenty-two million, one hundred two thousand, twenty-two".

Divisors: 1 2 55000511051011 110001022102022