1100011000117 has 2 divisors, whose sum is σ = 1100011000118. Its totient is φ = 1100011000116.

The previous prime is 1100011000103. The next prime is 1100011000183. The reversal of 1100011000117 is 7110001100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 764585852836 + 335425147281 = 874406^2 + 579159^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100011000117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100011000097 and 1100011000106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100011000817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005500058 + 550005500059.

It is an arithmetic number, because the mean of its divisors is an integer number (550005500059).

Almost surely, 2^{1100011000117} is an apocalyptic number.

It is an amenable number.

1100011000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100011000117 is an equidigital number, since it uses as much as digits as its factorization.

1100011000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7, while the sum is 13.

Adding to 1100011000117 its reverse (7110001100011), we get a palindrome (8210012100128).

It can be divided in two parts, 110001100011 and 7, that multiplied together give a palindrome (770007700077).

The spelling of 1100011000117 in words is "one trillion, one hundred billion, eleven million, one hundred seventeen", and thus it is an aban number.