11000112199981 has 2 divisors, whose sum is σ = 11000112199982. Its totient is φ = 11000112199980.

The previous prime is 11000112199897. The next prime is 11000112200009. The reversal of 11000112199981 is 18999121100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6924292274025 + 4075819925956 = 2631405^2 + 2018866^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000112199981 - 2¹⁷ = 11000112068909 is a prime.

It is a super-2 number, since 2×11000112199981² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000112199481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500056099990 + 5500056099991.

It is an arithmetic number, because the mean of its divisors is an integer number (5500056099991).

Almost surely, 2^{11000112199981} is an apocalyptic number.

It is an amenable number.

11000112199981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000112199981 is an equidigital number, since it uses as much as digits as its factorization.

11000112199981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11664, while the sum is 43.

Adding to 11000112199981 its reverse (18999121100011), we get a palindrome (29999233299992).

The spelling of 11000112199981 in words is "eleven trillion, one hundred twelve million, one hundred ninety-nine thousand, nine hundred eighty-one".