Base | Representation |
---|---|
bin | 10100011111010100… |
… | …00110111111000111 |
3 | 1001101121122202011222 |
4 | 22033222012333013 |
5 | 140012012141033 |
6 | 5015310350555 |
7 | 536410302353 |
oct | 121752067707 |
9 | 31347582158 |
10 | 11000115143 |
11 | 4735307356 |
12 | 216babb45b |
13 | 1063c67b94 |
14 | 764d00463 |
15 | 445ab3598 |
hex | 28fa86fc7 |
11000115143 has 2 divisors, whose sum is σ = 11000115144. Its totient is φ = 11000115142.
The previous prime is 11000115127. The next prime is 11000115163. The reversal of 11000115143 is 34151100011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000115143 - 24 = 11000115127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000115163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500057571 + 5500057572.
It is an arithmetic number, because the mean of its divisors is an integer number (5500057572).
Almost surely, 211000115143 is an apocalyptic number.
11000115143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000115143 is an equidigital number, since it uses as much as digits as its factorization.
11000115143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 11000115143 its reverse (34151100011), we get a palindrome (45151215154).
The spelling of 11000115143 in words is "eleven billion, one hundred fifteen thousand, one hundred forty-three".
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