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110001212002133 is a prime number
BaseRepresentation
bin11001000000101110100111…
…001010101000111101010101
3112102111000100121010212110222
4121000232213022220331111
5103404224440233032013
61025541505325124125
732112216402413504
oct3100564712507525
9472430317125428
10110001212002133
11320602854a4351
1210406b7b3b9645
13494c0ba40889a
141d24130cb683b
15cab5b5d1e508
hex640ba72a8f55

110001212002133 has 2 divisors, whose sum is σ = 110001212002134. Its totient is φ = 110001212002132.

The previous prime is 110001212002069. The next prime is 110001212002153. The reversal of 110001212002133 is 331200212100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108824579337604 + 1176632664529 = 10431902^2 + 1084727^2 .

It is a cyclic number.

It is not a de Polignac number, because 110001212002133 - 26 = 110001212002069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110001212002153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000606001066 + 55000606001067.

It is an arithmetic number, because the mean of its divisors is an integer number (55000606001067).

Almost surely, 2110001212002133 is an apocalyptic number.

It is an amenable number.

110001212002133 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001212002133 is an equidigital number, since it uses as much as digits as its factorization.

110001212002133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 110001212002133 its reverse (331200212100011), we get a palindrome (441201424102144).

The spelling of 110001212002133 in words is "one hundred ten trillion, one billion, two hundred twelve million, two thousand, one hundred thirty-three".