Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …000100110010111010101 |
3 | 10220011022210112110012110 |
4 | 100000131320212113111 |
5 | 121010311312113440 |
6 | 2201201120141233 |
7 | 142321230155541 |
oct | 20003570462725 |
9 | 3804283473173 |
10 | 1100013004245 |
11 | 394570733301 |
12 | 159234167819 |
13 | 7c9666ac3ac |
14 | 3b3530d0a21 |
15 | 1d931bbe080 |
hex | 1001de265d5 |
1100013004245 has 32 divisors (see below), whose sum is σ = 1821080880000. Its totient is φ = 566328460544.
The previous prime is 1100013004201. The next prime is 1100013004249. The reversal of 1100013004245 is 5424003100011.
It is a cyclic number.
It is not a de Polignac number, because 1100013004245 - 211 = 1100013002197 is a prime.
It is a super-2 number, since 2×11000130042452 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100013004249) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1909006 + ... + 2417504.
It is an arithmetic number, because the mean of its divisors is an integer number (56908777500).
Almost surely, 21100013004245 is an apocalyptic number.
1100013004245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1100013004245 is a deficient number, since it is larger than the sum of its proper divisors (721067875755).
1100013004245 is a wasteful number, since it uses less digits than its factorization.
1100013004245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 513509.
The product of its (nonzero) digits is 480, while the sum is 21.
Adding to 1100013004245 its reverse (5424003100011), we get a palindrome (6524016104256).
The spelling of 1100013004245 in words is "one trillion, one hundred billion, thirteen million, four thousand, two hundred forty-five".
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