Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …000101010011111001100 |
3 | 10220011022210120022100220 |
4 | 100000131320222133030 |
5 | 121010311313134012 |
6 | 2201201120351340 |
7 | 142321230256014 |
oct | 20003570523714 |
9 | 3804283508326 |
10 | 1100013021132 |
11 | 394570744a63 |
12 | 159234175550 |
13 | 7c9666b6c9c |
14 | 3b3530d6c44 |
15 | 1d931bc408c |
hex | 1001de2a7cc |
1100013021132 has 24 divisors (see below), whose sum is σ = 2566834297776. Its totient is φ = 366651400128.
The previous prime is 1100013021127. The next prime is 1100013021143. The reversal of 1100013021132 is 2311203100011.
It is a happy number.
It is a super-2 number, since 2×11000130211322 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2216203 + ... + 2666754.
It is an arithmetic number, because the mean of its divisors is an integer number (106951429074).
Almost surely, 21100013021132 is an apocalyptic number.
1100013021132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1100013021132 is an abundant number, since it is smaller than the sum of its proper divisors (1466821276644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1100013021132 is a wasteful number, since it uses less digits than its factorization.
1100013021132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4901737 (or 4901735 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 1100013021132 its reverse (2311203100011), we get a palindrome (3411216121143).
The spelling of 1100013021132 in words is "one trillion, one hundred billion, thirteen million, twenty-one thousand, one hundred thirty-two".
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