1100013233129 has 2 divisors, whose sum is σ = 1100013233130. Its totient is φ = 1100013233128.

The previous prime is 1100013233101. The next prime is 1100013233149. The reversal of 1100013233129 is 9213323100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1002497557504 + 97515675625 = 1001248^2 + 312275^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100013233129 - 2³⁶ = 1031293756393 is a prime.

It is a super-2 number, since 2×1100013233129² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100013233098 and 1100013233107.

It is not a weakly prime, because it can be changed into another prime (1100013233149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006616564 + 550006616565.

It is an arithmetic number, because the mean of its divisors is an integer number (550006616565).

Almost surely, 2^{1100013233129} is an apocalyptic number.

It is an amenable number.

1100013233129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013233129 is an equidigital number, since it uses as much as digits as its factorization.

1100013233129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 26.

The spelling of 1100013233129 in words is "one trillion, one hundred billion, thirteen million, two hundred thirty-three thousand, one hundred twenty-nine".