Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …001110001101100010111 |
3 | 10220011022211010010110002 |
4 | 100000131321301230113 |
5 | 121010311402002131 |
6 | 2201201130521515 |
7 | 142321232612231 |
oct | 20003571615427 |
9 | 3804284103402 |
10 | 1100013312791 |
11 | 3945709240a8 |
12 | 15923429629b |
13 | 7c966789973 |
14 | 3b353171251 |
15 | 1d931c306cb |
hex | 1001de71b17 |
1100013312791 has 2 divisors, whose sum is σ = 1100013312792. Its totient is φ = 1100013312790.
The previous prime is 1100013312787. The next prime is 1100013312829. The reversal of 1100013312791 is 1972133100011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100013312791 - 22 = 1100013312787 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100013312781) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006656395 + 550006656396.
It is an arithmetic number, because the mean of its divisors is an integer number (550006656396).
Almost surely, 21100013312791 is an apocalyptic number.
1100013312791 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100013312791 is an equidigital number, since it uses as much as digits as its factorization.
1100013312791 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 29.
The spelling of 1100013312791 in words is "one trillion, one hundred billion, thirteen million, three hundred twelve thousand, seven hundred ninety-one".
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