Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …110011110011100111101 |
3 | 10220011022220102201022101 |
4 | 100000131332132130331 |
5 | 121010312210412301 |
6 | 2201201213145101 |
7 | 142321246232632 |
oct | 20003576363475 |
9 | 3804286381271 |
10 | 1100014544701 |
11 | 394571595706 |
12 | 15923478b191 |
13 | 7c966acb5c7 |
14 | 3b3533b2189 |
15 | 1d931dc5701 |
hex | 1001df9e73d |
1100014544701 has 2 divisors, whose sum is σ = 1100014544702. Its totient is φ = 1100014544700.
The previous prime is 1100014544687. The next prime is 1100014544719. The reversal of 1100014544701 is 1074454100011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1088420639076 + 11593905625 = 1043274^2 + 107675^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100014544701 - 233 = 1091424610109 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1100014544701.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100014544791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550007272350 + 550007272351.
It is an arithmetic number, because the mean of its divisors is an integer number (550007272351).
Almost surely, 21100014544701 is an apocalyptic number.
It is an amenable number.
1100014544701 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100014544701 is an equidigital number, since it uses as much as digits as its factorization.
1100014544701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2240, while the sum is 28.
Adding to 1100014544701 its reverse (1074454100011), we get a palindrome (2174468644712).
The spelling of 1100014544701 in words is "one trillion, one hundred billion, fourteen million, five hundred forty-four thousand, seven hundred one".
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