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11000199383 is a prime number
BaseRepresentation
bin10100011111010100…
…11011100011010111
31001101121211000201222
422033222123203113
5140012022340013
65015312240555
7536411103065
oct121752334327
931347730658
1011000199383
114735364678
12216bb4015b
131063c97324
14764d23035
15445acd508
hex28fa9b8d7

11000199383 has 2 divisors, whose sum is σ = 11000199384. Its totient is φ = 11000199382.

The previous prime is 11000199373. The next prime is 11000199437. The reversal of 11000199383 is 38399100011.

It is a weak prime.

It is an emirp because it is prime and its reverse (38399100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000199383 - 218 = 10999937239 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000199373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500099691 + 5500099692.

It is an arithmetic number, because the mean of its divisors is an integer number (5500099692).

Almost surely, 211000199383 is an apocalyptic number.

11000199383 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000199383 is an equidigital number, since it uses as much as digits as its factorization.

11000199383 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 35.

Adding to 11000199383 its reverse (38399100011), we get a palindrome (49399299394).

The spelling of 11000199383 in words is "eleven billion, one hundred ninety-nine thousand, three hundred eighty-three".