Base | Representation |
---|---|
bin | 10000000000011110010… |
… | …011010010010111001111 |
3 | 10220011100021200212212011 |
4 | 100000132103102113033 |
5 | 121010320110001312 |
6 | 2201201530122051 |
7 | 142321343504122 |
oct | 20003623222717 |
9 | 3804307625764 |
10 | 1100020000207 |
11 | 394574681497 |
12 | 159236580327 |
13 | 7c967c8b80b |
14 | 3b353dd23b9 |
15 | 1d932601da7 |
hex | 1001e4d25cf |
1100020000207 has 2 divisors, whose sum is σ = 1100020000208. Its totient is φ = 1100020000206.
The previous prime is 1100020000159. The next prime is 1100020000243. The reversal of 1100020000207 is 7020000200011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100020000207 - 211 = 1100019998159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100020000507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550010000103 + 550010000104.
It is an arithmetic number, because the mean of its divisors is an integer number (550010000104).
Almost surely, 21100020000207 is an apocalyptic number.
1100020000207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100020000207 is an equidigital number, since it uses as much as digits as its factorization.
1100020000207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 13.
Adding to 1100020000207 its reverse (7020000200011), we get a palindrome (8120020200218).
The spelling of 1100020000207 in words is "one trillion, one hundred billion, twenty million, two hundred seven", and thus it is an aban number.
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