Search a number
-
+
11000200112281 is a prime number
BaseRepresentation
bin1010000000010010111100…
…0001010010100010011001
31102221121102212012102202101
42200010233001102202121
52420211402212043111
635221231104403401
72213511133126132
oct240045701224231
942847385172671
1011000200112281
113561182209266
121297ab4916561
1361a411a1a4a3
142a05abd86c89
15141219036bc1
hexa012f052899

11000200112281 has 2 divisors, whose sum is σ = 11000200112282. Its totient is φ = 11000200112280.

The previous prime is 11000200112273. The next prime is 11000200112327. The reversal of 11000200112281 is 18221100200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9492930723600 + 1507269388681 = 3081060^2 + 1227709^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000200112281 - 23 = 11000200112273 is a prime.

It is a super-2 number, since 2×110002001122812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11000200112581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500100056140 + 5500100056141.

It is an arithmetic number, because the mean of its divisors is an integer number (5500100056141).

Almost surely, 211000200112281 is an apocalyptic number.

It is an amenable number.

11000200112281 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000200112281 is an equidigital number, since it uses as much as digits as its factorization.

11000200112281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 11000200112281 its reverse (18221100200011), we get a palindrome (29221300312292).

The spelling of 11000200112281 in words is "eleven trillion, two hundred million, one hundred twelve thousand, two hundred eighty-one".