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11000201210993 is a prime number
BaseRepresentation
bin1010000000010010111100…
…0101011110110001110001
31102221121102221021020220102
42200010233011132301301
52420211403002222433
635221231144122145
72213511145353311
oct240045705366161
942847387236812
1011000201210993
113561182899795
121297ab5166355
1361a412013607
142a05ac191441
151412191a24e8
hexa012f15ec71

11000201210993 has 2 divisors, whose sum is σ = 11000201210994. Its totient is φ = 11000201210992.

The previous prime is 11000201210963. The next prime is 11000201211071. The reversal of 11000201210993 is 39901210200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10954299433984 + 45901777009 = 3309728^2 + 214247^2 .

It is an emirp because it is prime and its reverse (39901210200011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000201210993 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000201210903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500100605496 + 5500100605497.

It is an arithmetic number, because the mean of its divisors is an integer number (5500100605497).

Almost surely, 211000201210993 is an apocalyptic number.

It is an amenable number.

11000201210993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000201210993 is an equidigital number, since it uses as much as digits as its factorization.

11000201210993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 11000201210993 in words is "eleven trillion, two hundred one million, two hundred ten thousand, nine hundred ninety-three".