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11000203011053 is a prime number
BaseRepresentation
bin1010000000010010111100…
…1100010110001111101101
31102221121110001122201010022
42200010233030112033231
52420211403432323203
635221231250451525
72213511166561304
oct240045714261755
942847401581108
1011000203011053
113561183909143
121297ab5893ba5
1361a4124c3a39
142a05ac4dd43b
1514121940aa38
hexa012f3163ed

11000203011053 has 2 divisors, whose sum is σ = 11000203011054. Its totient is φ = 11000203011052.

The previous prime is 11000203010963. The next prime is 11000203011067. The reversal of 11000203011053 is 35011030200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9814417043209 + 1185785967844 = 3132797^2 + 1088938^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000203011053 - 212 = 11000203006957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000203011253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500101505526 + 5500101505527.

It is an arithmetic number, because the mean of its divisors is an integer number (5500101505527).

Almost surely, 211000203011053 is an apocalyptic number.

It is an amenable number.

11000203011053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000203011053 is an equidigital number, since it uses as much as digits as its factorization.

11000203011053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 11000203011053 its reverse (35011030200011), we get a palindrome (46011233211064).

The spelling of 11000203011053 in words is "eleven trillion, two hundred three million, eleven thousand, fifty-three".