Base | Representation |
---|---|
bin | 10100011111010100… |
… | …11110001111100011 |
3 | 1001101121211120212010 |
4 | 22033222132033203 |
5 | 140012023213103 |
6 | 5015312404003 |
7 | 536411150160 |
oct | 121752361743 |
9 | 31347746763 |
10 | 11000210403 |
11 | 4735371986 |
12 | 216bb46603 |
13 | 1063c9c350 |
14 | 764d27067 |
15 | 445ad1903 |
hex | 28fa9e3e3 |
11000210403 has 32 divisors (see below), whose sum is σ = 18071312896. Its totient is φ = 5795981568.
The previous prime is 11000210399. The next prime is 11000210423. The reversal of 11000210403 is 30401200011.
It is a happy number.
It is not a de Polignac number, because 11000210403 - 22 = 11000210399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11000210423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 234300 + ... + 277302.
It is an arithmetic number, because the mean of its divisors is an integer number (564728528).
Almost surely, 211000210403 is an apocalyptic number.
11000210403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11000210403 is a deficient number, since it is larger than the sum of its proper divisors (7071102493).
11000210403 is a wasteful number, since it uses less digits than its factorization.
11000210403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43963.
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 11000210403 its reverse (30401200011), we get a palindrome (41401410414).
The spelling of 11000210403 in words is "eleven billion, two hundred ten thousand, four hundred three".
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