Base | Representation |
---|---|
bin | 10100011111010100… |
… | …11110011000111011 |
3 | 1001101121211121200100 |
4 | 22033222132120323 |
5 | 140012023223003 |
6 | 5015312410443 |
7 | 536411152005 |
oct | 121752363073 |
9 | 31347747610 |
10 | 11000211003 |
11 | 4735372381 |
12 | 216bb46a23 |
13 | 1063c9c6c2 |
14 | 764d27375 |
15 | 445ad1ba3 |
hex | 28fa9e63b |
11000211003 has 24 divisors (see below), whose sum is σ = 16337589840. Its totient is φ = 7129062720.
The previous prime is 11000210971. The next prime is 11000211017. The reversal of 11000211003 is 30011200011.
It is not a de Polignac number, because 11000211003 - 25 = 11000210971 is a prime.
It is a super-2 number, since 2×110002110032 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is not an unprimeable number, because it can be changed into a prime (11000211043) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 53793 + ... + 157778.
It is an arithmetic number, because the mean of its divisors is an integer number (680732910).
Almost surely, 211000211003 is an apocalyptic number.
11000211003 is a deficient number, since it is larger than the sum of its proper divisors (5337378837).
11000211003 is a wasteful number, since it uses less digits than its factorization.
11000211003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211739 (or 211736 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
Adding to 11000211003 its reverse (30011200011), we get a palindrome (41011411014).
The spelling of 11000211003 in words is "eleven billion, two hundred eleven thousand, three".
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