Search a number
-
+
11000211003 = 3253109211571
BaseRepresentation
bin10100011111010100…
…11110011000111011
31001101121211121200100
422033222132120323
5140012023223003
65015312410443
7536411152005
oct121752363073
931347747610
1011000211003
114735372381
12216bb46a23
131063c9c6c2
14764d27375
15445ad1ba3
hex28fa9e63b

11000211003 has 24 divisors (see below), whose sum is σ = 16337589840. Its totient is φ = 7129062720.

The previous prime is 11000210971. The next prime is 11000211017. The reversal of 11000211003 is 30011200011.

It is not a de Polignac number, because 11000211003 - 25 = 11000210971 is a prime.

It is a super-2 number, since 2×110002110032 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is not an unprimeable number, because it can be changed into a prime (11000211043) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 53793 + ... + 157778.

It is an arithmetic number, because the mean of its divisors is an integer number (680732910).

Almost surely, 211000211003 is an apocalyptic number.

11000211003 is a deficient number, since it is larger than the sum of its proper divisors (5337378837).

11000211003 is a wasteful number, since it uses less digits than its factorization.

11000211003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211739 (or 211736 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

Adding to 11000211003 its reverse (30011200011), we get a palindrome (41011411014).

The spelling of 11000211003 in words is "eleven billion, two hundred eleven thousand, three".

Divisors: 1 3 9 53 109 159 327 477 981 5777 17331 51993 211571 634713 1904139 11213263 23061239 33639789 69183717 100919367 207551151 1222245667 3666737001 11000211003