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1100021121211 is a prime number
BaseRepresentation
bin10000000000011110010…
…111100100000010111011
310220011100100210211120211
4100000132113210002323
5121010320401334321
62201202010131551
7142321356153265
oct20003627440273
93804310724524
101100021121211
11394575277741
12159236a20bb7
137c968291b2c
143b354204b35
151d9327740e1
hex1001e5e40bb

1100021121211 has 2 divisors, whose sum is σ = 1100021121212. Its totient is φ = 1100021121210.

The previous prime is 1100021121193. The next prime is 1100021121239. The reversal of 1100021121211 is 1121211200011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100021121211 - 25 = 1100021121179 is a prime.

It is a super-2 number, since 2×11000211212112 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100021121191 and 1100021121200.

It is not a weakly prime, because it can be changed into another prime (1100021121281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550010560605 + 550010560606.

It is an arithmetic number, because the mean of its divisors is an integer number (550010560606).

Almost surely, 21100021121211 is an apocalyptic number.

1100021121211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100021121211 is an equidigital number, since it uses as much as digits as its factorization.

1100021121211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1100021121211 its reverse (1121211200011), we get a palindrome (2221232321222).

The spelling of 1100021121211 in words is "one trillion, one hundred billion, twenty-one million, one hundred twenty-one thousand, two hundred eleven".