Base | Representation |
---|---|
bin | 10000000000011110010… |
… | …111110101110101101101 |
3 | 10220011100100221112120011 |
4 | 100000132113311311231 |
5 | 121010320411202333 |
6 | 2201202011453221 |
7 | 142321356605623 |
oct | 20003627656555 |
9 | 3804310845504 |
10 | 1100021194093 |
11 | 394575317478 |
12 | 159236a57211 |
13 | 7c9682b9063 |
14 | 3b354223513 |
15 | 1d93278a9cd |
hex | 1001e5f5d6d |
1100021194093 has 2 divisors, whose sum is σ = 1100021194094. Its totient is φ = 1100021194092.
The previous prime is 1100021194039. The next prime is 1100021194109. The reversal of 1100021194093 is 3904911200011.
Together with previous prime (1100021194039) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 953851082409 + 146170111684 = 976653^2 + 382322^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100021194093 - 217 = 1100021063021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100021198093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550010597046 + 550010597047.
It is an arithmetic number, because the mean of its divisors is an integer number (550010597047).
Almost surely, 21100021194093 is an apocalyptic number.
It is an amenable number.
1100021194093 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100021194093 is an equidigital number, since it uses as much as digits as its factorization.
1100021194093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 31.
The spelling of 1100021194093 in words is "one trillion, one hundred billion, twenty-one million, one hundred ninety-four thousand, ninety-three".
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