Base | Representation |
---|---|
bin | 11001000000101111011101… |
… | …011010011000110100100111 |
3 | 112102111002201000122122001122 |
4 | 121000233131122120310213 |
5 | 103404233321224200012 |
6 | 1025542135515444155 |
7 | 32112251063210204 |
oct | 3100573532306447 |
9 | 472432630578048 |
10 | 110002122100007 |
11 | 320607021a3355 |
12 | 1040719415665b |
13 | 494c203b29537 |
14 | 1d241b9b00cab |
15 | cab61ab92e72 |
hex | 640bdd698d27 |
110002122100007 has 2 divisors, whose sum is σ = 110002122100008. Its totient is φ = 110002122100006.
The previous prime is 110002122099997. The next prime is 110002122100049. The reversal of 110002122100007 is 700001221200011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110002122100007 - 210 = 110002122098983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110002122109007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001061050003 + 55001061050004.
It is an arithmetic number, because the mean of its divisors is an integer number (55001061050004).
Almost surely, 2110002122100007 is an apocalyptic number.
110002122100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
110002122100007 is an equidigital number, since it uses as much as digits as its factorization.
110002122100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 110002122100007 its reverse (700001221200011), we get a palindrome (810003343300018).
The spelling of 110002122100007 in words is "one hundred ten trillion, two billion, one hundred twenty-two million, one hundred thousand, seven".
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