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110002201021117 is a prime number
BaseRepresentation
bin11001000000101111100010…
…000111011100101010111101
3112102111002220112011020110201
4121000233202013130222331
5103404234001430133432
61025542151415203501
732112253042060666
oct3100574207345275
9472432815136421
10110002201021117
11320607427a7a09
12104071b6676591
13494c21729c812
141d241c63a636d
15cab622a81ee7
hex640be21dcabd

110002201021117 has 2 divisors, whose sum is σ = 110002201021118. Its totient is φ = 110002201021116.

The previous prime is 110002201021099. The next prime is 110002201021133. The reversal of 110002201021117 is 711120102200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106388270751961 + 3613930269156 = 10314469^2 + 1901034^2 .

It is a cyclic number.

It is not a de Polignac number, because 110002201021117 - 243 = 101206107998909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110002201021094 and 110002201021103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110002201021217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001100510558 + 55001100510559.

It is an arithmetic number, because the mean of its divisors is an integer number (55001100510559).

Almost surely, 2110002201021117 is an apocalyptic number.

It is an amenable number.

110002201021117 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002201021117 is an equidigital number, since it uses as much as digits as its factorization.

110002201021117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 110002201021117 its reverse (711120102200011), we get a palindrome (821122303221128).

The spelling of 110002201021117 in words is "one hundred ten trillion, two billion, two hundred one million, twenty-one thousand, one hundred seventeen".