Base | Representation |
---|---|
bin | 10100011111010101… |
… | …00000110110111101 |
3 | 1001101121212010112221 |
4 | 22033222200312331 |
5 | 140012024033432 |
6 | 5015312525341 |
7 | 536411223334 |
oct | 121752406675 |
9 | 31347763487 |
10 | 11000221117 |
11 | 4735379a36 |
12 | 216bb50851 |
13 | 1063ca41a2 |
14 | 764d2ad1b |
15 | 445ad4b97 |
hex | 28faa0dbd |
11000221117 has 2 divisors, whose sum is σ = 11000221118. Its totient is φ = 11000221116.
The previous prime is 11000221051. The next prime is 11000221123. The reversal of 11000221117 is 71112200011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7507529316 + 3492691801 = 86646^2 + 59099^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000221117 - 215 = 11000188349 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11000221117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000221417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500110558 + 5500110559.
It is an arithmetic number, because the mean of its divisors is an integer number (5500110559).
Almost surely, 211000221117 is an apocalyptic number.
It is an amenable number.
11000221117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000221117 is an equidigital number, since it uses as much as digits as its factorization.
11000221117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28, while the sum is 16.
Adding to 11000221117 its reverse (71112200011), we get a palindrome (82112421128).
The spelling of 11000221117 in words is "eleven billion, two hundred twenty-one thousand, one hundred seventeen".
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