Base | Representation |
---|---|
bin | 10000000000011110011… |
… | …011011010110100001111 |
3 | 10220011100102201012002211 |
4 | 100000132123122310033 |
5 | 121010321131210413 |
6 | 2201202043531251 |
7 | 142321400563165 |
oct | 20003633326417 |
9 | 3804312635084 |
10 | 1100022131983 |
11 | 3945758a8095 |
12 | 159237229b27 |
13 | 7c968556c18 |
14 | 3b3543c9235 |
15 | 1d9328c383d |
hex | 1001e6dad0f |
1100022131983 has 2 divisors, whose sum is σ = 1100022131984. Its totient is φ = 1100022131982.
The previous prime is 1100022131951. The next prime is 1100022132023. The reversal of 1100022131983 is 3891312200011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100022131983 - 25 = 1100022131951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100022131903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550011065991 + 550011065992.
It is an arithmetic number, because the mean of its divisors is an integer number (550011065992).
Almost surely, 21100022131983 is an apocalyptic number.
1100022131983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100022131983 is an equidigital number, since it uses as much as digits as its factorization.
1100022131983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 31.
Adding to 1100022131983 its reverse (3891312200011), we get a palindrome (4991334331994).
The spelling of 1100022131983 in words is "one trillion, one hundred billion, twenty-two million, one hundred thirty-one thousand, nine hundred eighty-three".
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