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1100022131983 is a prime number
BaseRepresentation
bin10000000000011110011…
…011011010110100001111
310220011100102201012002211
4100000132123122310033
5121010321131210413
62201202043531251
7142321400563165
oct20003633326417
93804312635084
101100022131983
113945758a8095
12159237229b27
137c968556c18
143b3543c9235
151d9328c383d
hex1001e6dad0f

1100022131983 has 2 divisors, whose sum is σ = 1100022131984. Its totient is φ = 1100022131982.

The previous prime is 1100022131951. The next prime is 1100022132023. The reversal of 1100022131983 is 3891312200011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100022131983 - 25 = 1100022131951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100022131903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550011065991 + 550011065992.

It is an arithmetic number, because the mean of its divisors is an integer number (550011065992).

Almost surely, 21100022131983 is an apocalyptic number.

1100022131983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100022131983 is an equidigital number, since it uses as much as digits as its factorization.

1100022131983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 31.

Adding to 1100022131983 its reverse (3891312200011), we get a palindrome (4991334331994).

The spelling of 1100022131983 in words is "one trillion, one hundred billion, twenty-two million, one hundred thirty-one thousand, nine hundred eighty-three".