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11000222201221 = 111000020200111
BaseRepresentation
bin1010000000010011000001…
…0101100011010110000101
31102221121111101202200002021
42200010300111203112011
52420211423340414341
635221233214043141
72213511521645311
oct240046025432605
942847441680067
1011000222201221
113561193725a90
121297b001a94b1
1361a416482676
142a05b0c96b41
1514121ae4b9d1
hexa0130563585

11000222201221 has 4 divisors (see below), whose sum is σ = 12000242401344. Its totient is φ = 10000202001100.

The previous prime is 11000222201119. The next prime is 11000222201233. The reversal of 11000222201221 is 12210222200011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000222201221 - 223 = 11000213812613 is a prime.

It is a super-2 number, since 2×110002222012212 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11000222201195 and 11000222201204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000222201321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500010100045 + ... + 500010100066.

It is an arithmetic number, because the mean of its divisors is an integer number (3000060600336).

Almost surely, 211000222201221 is an apocalyptic number.

11000222201221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11000222201221 is a deficient number, since it is larger than the sum of its proper divisors (1000020200123).

11000222201221 is a wasteful number, since it uses less digits than its factorization.

11000222201221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000020200122.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 11000222201221 its reverse (12210222200011), we get a palindrome (23210444401232).

It can be divided in two parts, 110002 and 22201221, that multiplied together give a palindrome (2442178712442).

The spelling of 11000222201221 in words is "eleven trillion, two hundred twenty-two million, two hundred one thousand, two hundred twenty-one".

Divisors: 1 11 1000020200111 11000222201221