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11000231100007 is a prime number
BaseRepresentation
bin1010000000010011000011…
…0111011111111001100111
31102221121112000111202220221
42200010300313133321213
52420211433130200012
635221234132505211
72213511660410302
oct240046067377147
942847460452827
1011000231100007
113561198753856
121297b0317b207
1361a418279c16
142a05b2131b39
1514121bb08507
hexa0130ddfe67

11000231100007 has 2 divisors, whose sum is σ = 11000231100008. Its totient is φ = 11000231100006.

The previous prime is 11000231099971. The next prime is 11000231100031. The reversal of 11000231100007 is 70000113200011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000231100007 is a prime.

It is a super-2 number, since 2×110002311000072 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000231100307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500115550003 + 5500115550004.

It is an arithmetic number, because the mean of its divisors is an integer number (5500115550004).

Almost surely, 211000231100007 is an apocalyptic number.

11000231100007 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000231100007 is an equidigital number, since it uses as much as digits as its factorization.

11000231100007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 16.

Adding to 11000231100007 its reverse (70000113200011), we get a palindrome (81000344300018).

The spelling of 11000231100007 in words is "eleven trillion, two hundred thirty-one million, one hundred thousand, seven".