Base | Representation |
---|---|
bin | 1010000000010011001000… |
… | …1011010111000011000011 |
3 | 1102221121120112212200002002 |
4 | 2200010302023113003003 |
5 | 2420212004242140333 |
6 | 35221240240014215 |
7 | 2213512345311152 |
oct | 240046213270303 |
9 | 42847515780062 |
10 | 11000253083843 |
11 | 35611aa0a9611 |
12 | 1297b0a60136b |
13 | 61a41c9a62ca |
14 | 2a05b5015599 |
15 | 14121d9ec0e8 |
hex | a01322d70c3 |
11000253083843 has 2 divisors, whose sum is σ = 11000253083844. Its totient is φ = 11000253083842.
The previous prime is 11000253083773. The next prime is 11000253083879. The reversal of 11000253083843 is 34838035200011.
It is a strong prime.
It is an emirp because it is prime and its reverse (34838035200011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11000253083843 - 212 = 11000253079747 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11000253083797 and 11000253083806.
It is not a weakly prime, because it can be changed into another prime (11000253083893) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500126541921 + 5500126541922.
It is an arithmetic number, because the mean of its divisors is an integer number (5500126541922).
Almost surely, 211000253083843 is an apocalyptic number.
11000253083843 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000253083843 is an equidigital number, since it uses as much as digits as its factorization.
11000253083843 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 38.
Adding to 11000253083843 its reverse (34838035200011), we get a palindrome (45838288283854).
The spelling of 11000253083843 in words is "eleven trillion, two hundred fifty-three million, eighty-three thousand, eight hundred forty-three".
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