Base | Representation |
---|---|
bin | 10100011111010101… |
… | …10100111011001101 |
3 | 1001101122000022022002 |
4 | 22033222310323031 |
5 | 140012034201214 |
6 | 5015314402045 |
7 | 536412015062 |
oct | 121752647315 |
9 | 31348008262 |
10 | 11000303309 |
11 | 4735425766 |
12 | 216bb90325 |
13 | 1064002718 |
14 | 764d4cc69 |
15 | 445aee1de |
hex | 28fab4ecd |
11000303309 has 2 divisors, whose sum is σ = 11000303310. Its totient is φ = 11000303308.
The previous prime is 11000303297. The next prime is 11000303323. The reversal of 11000303309 is 90330300011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10486374409 + 513928900 = 102403^2 + 22670^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000303309 - 220 = 10999254733 is a prime.
It is a super-3 number, since 3×110003033093 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000303399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500151654 + 5500151655.
It is an arithmetic number, because the mean of its divisors is an integer number (5500151655).
Almost surely, 211000303309 is an apocalyptic number.
It is an amenable number.
11000303309 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000303309 is an equidigital number, since it uses as much as digits as its factorization.
11000303309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
The spelling of 11000303309 in words is "eleven billion, three hundred three thousand, three hundred nine".
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