11000311139 has 2 divisors, whose sum is σ = 11000311140. Its totient is φ = 11000311138.

The previous prime is 11000311129. The next prime is 11000311141. The reversal of 11000311139 is 93111300011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000311139 - 2⁴ = 11000311123 is a prime.

It is a super-3 number, since 3×11000311139³ (a number of 31 digits) contains 333 as substring.

Together with 11000311141, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11000311139.

It is not a weakly prime, because it can be changed into another prime (11000311129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500155569 + 5500155570.

It is an arithmetic number, because the mean of its divisors is an integer number (5500155570).

Almost surely, 2^11000311139 is an apocalyptic number.

11000311139 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000311139 is an equidigital number, since it uses as much as digits as its factorization.

11000311139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 11000311139 in words is "eleven billion, three hundred eleven thousand, one hundred thirty-nine".