11000311300 has 72 divisors (see below), whose sum is σ = 26091892512. Its totient is φ = 3992256000.

The previous prime is 11000311253. The next prime is 11000311303. The reversal of 11000311300 is 311300011.

11000311300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×11000311300³ (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is not an unprimeable number, because it can be changed into a prime (11000311303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 565740 + ... + 584860.

It is an arithmetic number, because the mean of its divisors is an integer number (362387396).

Almost surely, 2^11000311300 is an apocalyptic number.

11000311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11000311300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13045946256).

11000311300 is an abundant number, since it is smaller than the sum of its proper divisors (15091581212).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000311300 is a wasteful number, since it uses less digits than its factorization.

11000311300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19669 (or 19662 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 11000311300 its reverse (311300011), we get a palindrome (11311611311).

The spelling of 11000311300 in words is "eleven billion, three hundred eleven thousand, three hundred".