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11000311332 = 2235317296087
BaseRepresentation
bin10100011111010101…
…10110111000100100
31001101122000201022020
422033222312320210
5140012034430312
65015314503140
7536412050343
oct121752667044
931348021266
1011000311332
11473543079a
12216bb94ab0
13106400627a
14764d51b5a
15445b0178c
hex28fab6e24

11000311332 has 24 divisors (see below), whose sum is σ = 26151685056. Its totient is φ = 3597585888.

The previous prime is 11000311303. The next prime is 11000311351. The reversal of 11000311332 is 23311300011.

It is a super-3 number, since 3×110003113323 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8647408 + ... + 8648679.

It is an arithmetic number, because the mean of its divisors is an integer number (1089653544).

Almost surely, 211000311332 is an apocalyptic number.

11000311332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11000311332 is an abundant number, since it is smaller than the sum of its proper divisors (15151373724).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000311332 is a wasteful number, since it uses less digits than its factorization.

11000311332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17296147 (or 17296145 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11000311332 its reverse (23311300011), we get a palindrome (34311611343).

The spelling of 11000311332 in words is "eleven billion, three hundred eleven thousand, three hundred thirty-two".

Divisors: 1 2 3 4 6 12 53 106 159 212 318 636 17296087 34592174 51888261 69184348 103776522 207553044 916692611 1833385222 2750077833 3666770444 5500155666 11000311332