Base | Representation |
---|---|
bin | 110011001110010110… |
… | …0100110100001100111 |
3 | 101111221022021111112012 |
4 | 1212130230212201213 |
5 | 3300241244321411 |
6 | 122311300344435 |
7 | 10642660044224 |
oct | 1463454464147 |
9 | 344838244465 |
10 | 110003120231 |
11 | 42719991414 |
12 | 1939b9a511b |
13 | a4b10501b4 |
14 | 547779694b |
15 | 2cdc51218b |
hex | 199cb26867 |
110003120231 has 2 divisors, whose sum is σ = 110003120232. Its totient is φ = 110003120230.
The previous prime is 110003120203. The next prime is 110003120251. The reversal of 110003120231 is 132021300011.
It is a strong prime.
It is an emirp because it is prime and its reverse (132021300011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110003120231 is a prime.
It is a super-3 number, since 3×1100031202313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110003120251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001560115 + 55001560116.
It is an arithmetic number, because the mean of its divisors is an integer number (55001560116).
Almost surely, 2110003120231 is an apocalyptic number.
110003120231 is a deficient number, since it is larger than the sum of its proper divisors (1).
110003120231 is an equidigital number, since it uses as much as digits as its factorization.
110003120231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 110003120231 its reverse (132021300011), we get a palindrome (242024420242).
The spelling of 110003120231 in words is "one hundred ten billion, three million, one hundred twenty thousand, two hundred thirty-one".
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