11000312093 has 2 divisors, whose sum is σ = 11000312094. Its totient is φ = 11000312092.

The previous prime is 11000312039. The next prime is 11000312107. The reversal of 11000312093 is 39021300011.

Together with previous prime (11000312039) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9968424964 + 1031887129 = 99842^2 + 32123^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000312093 - 2²² = 10996117789 is a prime.

It is a super-3 number, since 3×11000312093³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000312023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500156046 + 5500156047.

It is an arithmetic number, because the mean of its divisors is an integer number (5500156047).

Almost surely, 2^11000312093 is an apocalyptic number.

It is an amenable number.

11000312093 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000312093 is an equidigital number, since it uses as much as digits as its factorization.

11000312093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

The spelling of 11000312093 in words is "eleven billion, three hundred twelve thousand, ninety-three".