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1100031212353 is a prime number
BaseRepresentation
bin10000000000011110111…
…110000011101101000001
310220011101001210112000211
4100000132332003231001
5121010330442243403
62201203010314121
7142321541012443
oct20003676035501
93804331715024
101100031212353
1139457aa3a327
1215923a288941
137c96a3b6018
143b3556b0493
151d9335b906d
hex1001ef83b41

1100031212353 has 2 divisors, whose sum is σ = 1100031212354. Its totient is φ = 1100031212352.

The previous prime is 1100031212351. The next prime is 1100031212431. The reversal of 1100031212353 is 3532121300011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 953653808704 + 146377403649 = 976552^2 + 382593^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100031212353 - 21 = 1100031212351 is a prime.

It is a super-3 number, since 3×11000312123533 (a number of 37 digits) contains 333 as substring.

Together with 1100031212351, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1100031212351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550015606176 + 550015606177.

It is an arithmetic number, because the mean of its divisors is an integer number (550015606177).

Almost surely, 21100031212353 is an apocalyptic number.

It is an amenable number.

1100031212353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100031212353 is an equidigital number, since it uses as much as digits as its factorization.

1100031212353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 1100031212353 its reverse (3532121300011), we get a palindrome (4632152512364).

The spelling of 1100031212353 in words is "one trillion, one hundred billion, thirty-one million, two hundred twelve thousand, three hundred fifty-three".