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1100031212422 = 2550015606211
BaseRepresentation
bin10000000000011110111…
…110000011101110000110
310220011101001210112010101
4100000132332003232012
5121010330442244142
62201203010314314
7142321541012602
oct20003676035606
93804331715111
101100031212422
1139457aa3a38a
1215923a28899a
137c96a3b606c
143b3556b0502
151d9335b90b7
hex1001ef83b86

1100031212422 has 4 divisors (see below), whose sum is σ = 1650046818636. Its totient is φ = 550015606210.

The previous prime is 1100031212353. The next prime is 1100031212431. The reversal of 1100031212422 is 2242121300011.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×11000312124223 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1100031212422.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275007803104 + ... + 275007803107.

It is an arithmetic number, because the mean of its divisors is an integer number (412511704659).

Almost surely, 21100031212422 is an apocalyptic number.

1100031212422 is a deficient number, since it is larger than the sum of its proper divisors (550015606214).

1100031212422 is an equidigital number, since it uses as much as digits as its factorization.

1100031212422 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 550015606213.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1100031212422 its reverse (2242121300011), we get a palindrome (3342152512433).

The spelling of 1100031212422 in words is "one trillion, one hundred billion, thirty-one million, two hundred twelve thousand, four hundred twenty-two".

Divisors: 1 2 550015606211 1100031212422