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1100032199953 is a prime number
BaseRepresentation
bin10000000000011111000…
…001110100110100010001
310220011101010122200202121
4100000133001310310101
5121010331220344303
62201203043414241
7142321552264651
oct20003701646421
93804333580677
101100032199953
11394580554325
1215923a684381
137c96a6706bb
143b35588a361
151d9337119bd
hex1001f074d11

1100032199953 has 2 divisors, whose sum is σ = 1100032199954. Its totient is φ = 1100032199952.

The previous prime is 1100032199947. The next prime is 1100032199977. The reversal of 1100032199953 is 3599912300011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1052208195984 + 47824003969 = 1025772^2 + 218687^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100032199953 - 213 = 1100032191761 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100032199993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550016099976 + 550016099977.

It is an arithmetic number, because the mean of its divisors is an integer number (550016099977).

Almost surely, 21100032199953 is an apocalyptic number.

It is an amenable number.

1100032199953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100032199953 is an equidigital number, since it uses as much as digits as its factorization.

1100032199953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 65610, while the sum is 43.

Adding to 1100032199953 its reverse (3599912300011), we get a palindrome (4699944499964).

The spelling of 1100032199953 in words is "one trillion, one hundred billion, thirty-two million, one hundred ninety-nine thousand, nine hundred fifty-three".