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1100032222013 is a prime number
BaseRepresentation
bin10000000000011111000…
…001111010001100111101
310220011101010200211000122
4100000133001322030331
5121010331222101023
62201203044104325
7142321552416164
oct20003701721475
93804333624018
101100032222013
1139458056995a
1215923a6950a5
137c96a67a75a
143b3558943db
151d9337182c8
hex1001f07a33d

1100032222013 has 2 divisors, whose sum is σ = 1100032222014. Its totient is φ = 1100032222012.

The previous prime is 1100032222007. The next prime is 1100032222027. The reversal of 1100032222013 is 3102222300011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1082708924089 + 17323297924 = 1040533^2 + 131618^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100032222013 - 230 = 1098958480189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100032221982 and 1100032222000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100032222813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550016111006 + 550016111007.

It is an arithmetic number, because the mean of its divisors is an integer number (550016111007).

Almost surely, 21100032222013 is an apocalyptic number.

It is an amenable number.

1100032222013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100032222013 is an equidigital number, since it uses as much as digits as its factorization.

1100032222013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1100032222013 its reverse (3102222300011), we get a palindrome (4202254522024).

The spelling of 1100032222013 in words is "one trillion, one hundred billion, thirty-two million, two hundred twenty-two thousand, thirteen".