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110003240114 = 255001620057
BaseRepresentation
bin110011001110010110…
…1000011110010110010
3101111221022111120222022
41212130231003302302
53300241312140424
6122311303111442
710642661053565
oct1463455036262
9344838446868
10110003240114
1142719a63499
121939ba42582
13a4b1092931
1454777c84dc
152cdc53795e
hex199cb43cb2

110003240114 has 4 divisors (see below), whose sum is σ = 165004860174. Its totient is φ = 55001620056.

The previous prime is 110003240077. The next prime is 110003240119. The reversal of 110003240114 is 411042300011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 107633205625 + 2370034489 = 328075^2 + 48683^2 .

It is a junction number, because it is equal to n+sod(n) for n = 110003240092 and 110003240101.

It is not an unprimeable number, because it can be changed into a prime (110003240119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500810027 + ... + 27500810030.

Almost surely, 2110003240114 is an apocalyptic number.

110003240114 is a deficient number, since it is larger than the sum of its proper divisors (55001620060).

110003240114 is an equidigital number, since it uses as much as digits as its factorization.

110003240114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55001620059.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 110003240114 its reverse (411042300011), we get a palindrome (521045540125).

The spelling of 110003240114 in words is "one hundred ten billion, three million, two hundred forty thousand, one hundred fourteen".

Divisors: 1 2 55001620057 110003240114