Base | Representation |
---|---|
bin | 10100011111010101… |
… | …11100001011010011 |
3 | 1001101122001211001011 |
4 | 22033222330023103 |
5 | 140012041124021 |
6 | 5015315151351 |
7 | 536412200503 |
oct | 121752741323 |
9 | 31348054034 |
10 | 11000333011 |
11 | 4735446008 |
12 | 216bba5557 |
13 | 10640130b5 |
14 | 764d59a03 |
15 | 445b07de1 |
hex | 28fabc2d3 |
11000333011 has 2 divisors, whose sum is σ = 11000333012. Its totient is φ = 11000333010.
The previous prime is 11000332979. The next prime is 11000333053. The reversal of 11000333011 is 11033300011.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (11033300011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11000333011 - 25 = 11000332979 is a prime.
It is a super-2 number, since 2×110003330112 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11000332982 and 11000333000.
It is not a weakly prime, because it can be changed into another prime (11000333711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500166505 + 5500166506.
It is an arithmetic number, because the mean of its divisors is an integer number (5500166506).
Almost surely, 211000333011 is an apocalyptic number.
11000333011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000333011 is an equidigital number, since it uses as much as digits as its factorization.
11000333011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 11000333011 its reverse (11033300011), we get a palindrome (22033633022).
The spelling of 11000333011 in words is "eleven billion, three hundred thirty-three thousand, eleven".
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