110003333122130 has 256 divisors, whose sum is σ = 239813140396032. Its totient is φ = 35548111872000.

The previous prime is 110003333122097. The next prime is 110003333122141. The reversal of 110003333122130 is 31221333300011.

It is a junction number, because it is equal to n+sod(n) for n = 110003333122096 and 110003333122105.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 9212231960 + ... + 9212243900.

It is an arithmetic number, because the mean of its divisors is an integer number (936770079672).

Almost surely, 2^{110003333122130} is an apocalyptic number.

110003333122130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

110003333122130 is an abundant number, since it is smaller than the sum of its proper divisors (129809807273902).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110003333122130 is a wasteful number, since it uses less digits than its factorization.

110003333122130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12973.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 110003333122130 its reverse (31221333300011), we get a palindrome (141224666422141).

The spelling of 110003333122130 in words is "one hundred ten trillion, three billion, three hundred thirty-three million, one hundred twenty-two thousand, one hundred thirty".