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1100043320 = 23527501083
BaseRepresentation
bin100000110010001…
…0101010000111000
32211122220222202012
41001210111100320
54223102341240
6301053425052
736155133245
oct10144252070
92748828665
101100043320
11514a44912
1226849b188
13146b9760c
14a61505cc
1566893b65
hex41915438

1100043320 has 16 divisors (see below), whose sum is σ = 2475097560. Its totient is φ = 440017312.

The previous prime is 1100043313. The next prime is 1100043349. The reversal of 1100043320 is 233400011.

It is a junction number, because it is equal to n+sod(n) for n = 1100043295 and 1100043304.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13750502 + ... + 13750581.

Almost surely, 21100043320 is an apocalyptic number.

1100043320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1100043320 is an abundant number, since it is smaller than the sum of its proper divisors (1375054240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1100043320 is a wasteful number, since it uses less digits than its factorization.

1100043320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27501094 (or 27501090 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 1100043320 is about 33166.9009706967. The cubic root of 1100043320 is about 1032.2936663011.

Adding to 1100043320 its reverse (233400011), we get a palindrome (1333443331).

The spelling of 1100043320 in words is "one billion, one hundred million, forty-three thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 20 40 27501083 55002166 110004332 137505415 220008664 275010830 550021660 1100043320